Wednesday, July 1, 2020
Quarter Wit, Quarter Wisdom Beware of Sneaky Answer Choices on the GMAT!
Test-takers often ask for tips and short cuts to cut down the amount of work necessary to solve a GMAT problem.à As such, the Testmaker might want to award the test-taker who pays attention to detail and puts in the required effort. Today, we will look at an example of this concept if it seems to be too easy, it is a trap! In the figure given above, the area of the equilateral triangle is 48. If the other three figures are squares, what is the perimeter, approximately, of the nine-sided shape they form? (A) 8âËÅ¡(2) (B) 24âËÅ¡(3) (C) 72âËÅ¡(2) (D) 144âËÅ¡(2) (E) 384 The first thing I notice aboutà this question is that we have anà equilateral triangle. So I am thinking, the area = s^2 * âËÅ¡(3)/4 and/or the altitude = s*âËÅ¡(3)/2. The irrational number in play is âËÅ¡(3). There is only oneà answer choice with âËÅ¡(3) in it, so will this be the answer? Now, it actually makes me uncomfortable that à there is only one option with âËÅ¡(3). At first glance, it seems that the answer has been served to us on a silver plate. But the question format doesnââ¬â¢t seem very easy it links two geometrical figures together. So I doubt very much that the correct answer would be that obvious. The next step willà be to think a bit harder: The area of the triangle has âËÅ¡(3) in it, so the side would be a further square root of âËÅ¡(3). This means the actual irrational number would be the fourth root of 3, but we donââ¬â¢t have any answer choice that has the fourth root of 3 in it. Letââ¬â¢s go deeper now and actually solve the question. The area of the equilateral triangle = Side^2 * (âËÅ¡(3)/4) = 48 Side^2 = 48*4/âËÅ¡(3) Side^2 = 4*4*4*3/âËÅ¡(3) Side = 8*FourthRoot(3) Now note that the side of the equilateral triangle is the same length as the sides of the squares, too. Hence, all sides of the three squares will be of length 8*FourthRoot(3). All nine sides of the figure are the sides of squares. Hence: The perimeter of the nine sided figure = 9*8*FourthRoot(3) The perimeter of the nine sided figure =72*FourthRoot(3) Now look at the answer choices. We have an option that isà 72âËÅ¡(2). The other answer choicesà are either much smaller or much greater than that. Think about ità the fourth root of 3 = âËÅ¡(âËÅ¡(3)) = âËÅ¡(1.732), which is actually very similar to âËÅ¡(2). Number properties will help you figure this out. Squares of smaller numbers (that are still greater than 1) are only a bit larger than the numbers themselves. For example: (1.1)^2 = 1.21 (1.2)^2 = 1.44 (1.3)^2 = 1.69 (1.414)^2 = 2 Since 1.732 is close to 1.69, the âËÅ¡(1.732) will be close to the âËÅ¡(1.69), i.e. 1.3. Also, âËÅ¡(2) = 1.414. The two values are quite close, therefore, the perimeter is approximately 72âËÅ¡(2). This is the reason the question specifically requests theà ââ¬Å"approximateâ⬠perimeter. We hope you see how the Testmaker could sneak in a tempting answer choiceà beware the easiest option! Getting ready to take the GMAT? We haveà free online GMAT seminarsà running all the time. And, be sure to follow us onà Facebook,à YouTube,à Google+, andà Twitter! Karishma, a Computer Engineer with a keen interest in alternative Mathematical approaches, has mentored students in the continents of Asia, Europe and North America. She teaches theà GMATà for Veritas Prep and regularly participates in content development projects such asà this blog!
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